The specific resistance P of a circular wire of-radius r- resistance R- and length - is given by P - -r-R-t -given r - 0-24 - 0-02cm- R - 30 - 1 n- and - - 4-80 - 0-01 cm- The percentage error in P is nearly- -

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Ohm's Law in Scalar Form

The specific ...

Question

The specific resistance P of a circular wire of radius r, resistance R, and length / is given by P = πr²R/t (given r = 0.24 + 0.02cm, R = 30 + 1 n, and / = 4.80 + 0.01 cm.) The percentage error in P is nearly??

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ρ

ρ = π r^{2} R / l

r = 0.24 \pm 0.02 c m, R = 30 \pm 1 Ω,

l = 4.80 \pm 0.01 c m .

ρ

ρ = π r^{2} R / l

r =

= 0.26 \pm 0.02 c m, l =

= 156.0 \pm 0.1 c m

R =

= 64 \pm 2 Ω

r

l

R

(0.2 0 \pm 0.01)

(800 \pm 0.1)

(301 \pm 1) Ω

ρ = \frac{π r^{2} R}{l}

(0.2 \pm 0.02)

(60 \pm 2) Ω

(150 \pm 0.1)

V = I R

P

I = \sqrt{\frac{P}{R}}

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