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Warm Air and Cool Air

The specific ...

Question

The specific volume of dry air in an air-water vapour mixture having temperature 24 $^{\circ}$ C relatice humidity 40% at standard barometric pressure 100 kPa if the saturated air pressure is 20 kPa is

0.93 m^{3} / k g o f d a

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4.26 m^{3} / k g o f d a

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10.65 m^{3} / k g o f d a

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0.85 m^{3} / k g o f d a

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Solution

The correct option is A $0.93 m^{3} / k g o f d a$
$T = 297 K$

$T_{v s} = 20 k P a$

$ϕ = \frac{P_{v}}{P_{v s}}$

$P_{v} = ϕ P_{v s} = 8 k P a$

$P_{a} = P - P_{v} = 100 - 8 = 92 k P a$

$v = \frac{R_{g} T}{P_{a}} = \frac{0.287 \times 297}{92} = 0.93 m^{3} / k g o f d r y a i r$

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