The specific weight of material used for the construction of a gravity dam is $24.5 k N / m^{3}$ . Uplift pressure acting on the dam is assumed to vary linearly from full hydrostatic head at heel to zero at toe of the dam. If the safe allowable pressure on the dam is 7.2 MPA, limiting height of the dam will be?

230 m

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290 m

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170 m

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330 m

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Solution

The correct option is B 290 m
Limiting height,
$H_{l i m} = \frac{f}{γ_{w} (G + 1 - C}$

Safe allowable stress,
$f = 7.2 M P a = 7.2 \times 10^{3} k N / m^{3}$

Given, uplift varies linearly from full hydrostatic head to zero
Then, uplift pressure coefficient (C) = 1

$H_{l i m} = \frac{7.2 \times 10^{3}}{9.81 \times (\frac{24.5}{9.81} + 1 - 1)} = 293.87 m$

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The correct option is B 290 mLimiting height, Hlim=fγw(G+1−C Safe allowable stress, f=7.2 MPa=7.2×103 kN/m3 Given, uplift varies linearly from full hydrostatic head to zero Then, uplift pressure coefficient (C) = 1 Hlim=7.2×1039.81×(24.59.81+1−1)=293.87 m