Question

The spectral lines of hydrogen-like atom fall within the wavelength range from $960\mathring{A}$ to $1350\mathring{A}$. Then Match the following :

Answer 1

$A)$ $E=-0.85eV=\frac{-13.6}{n^2}{n}^2=16n=4$

Energy released $=+13.6-0.85=\frac{hc}{\lambda }12.75=\frac{hc}{\lambda }$

$\lambda =970$ ${}^{o}A$

So, $\left(A\right)\to \left(4\right)$

$B)$ $E=-3.4=\frac{-13.6}{n^2}\Rightarrow n^2=4n=2E=10.2=\frac{hc}{\lambda }\Rightarrow \lambda =1212$

So, $\left(B\right)\to \left(1\right)$

$C)$ $E=-13.6\times 9=122.4$

So, $\left(C\right)\to \left(2\right)$

$D)$ $E=-13.6\times 4\approx 303$

So, $\left(D\right)\to \left(3\right)$