M(f)=10−3rect(f2000)
So, fm(max)=1000Hz=1kHz
m(t)=2 sinc(2000t)V
So, |m(t)|(max)=2V
Maximum frequency deviation
Δf=kf|m(t)|max=(10kHz/V)×2V=20kHz
Deviation ratio, D=Δffm(max)=201=20
BandwidthBW=(1+D)2fm(max)
= ( 1 + 20 )(2)(1)kHz
= 42 kHz