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Question

The speed at the maximum height of a projectile is 32 times of the initial speed is u of projection. Its range on the horizontal plane

A
3u22g
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B
u22g
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C
3u22g
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D
3u2g
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Solution

The correct option is C 3u22g
Lets consider, u= initial velocity of the projectile
θ= angle of projection
At the maximum height, vertical component is vanished and the horizontal component is ucosθ
ucosθ=3u2
cosθ=32
θ=cos1(32)
θ=300
Horizonal range, R=u2sin2θg
R=u2sin600g
R=3u22g
The correct option is A.

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