The speed of a body is doubled when it moves over a distance of 10m. If the initial speed be u, what will be the speed after further coverage of distance 10m?
A
√5u
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B
√6u
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C
√7u
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D
√8u
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Solution
The correct option is C√7u If the acceleration be a then using the third equation of motion, v2=u2+2as
we have (2u)2=u2+2a×10 so a=3u2/20....(1)
After further covering 10 m taking initial speed at the moment it has covered the first10m as 2u we get v2=(2u)2+2a×10 , putting value of a from equation-1 we get v2=√7u