The speed of an electron in the ground state of hydrogen atom is:

2.186 \times 10^{5} m s^{- 2}

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2.186 \times 10^{6} m s^{- 1}

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2.186 \times 10^{6} m s^{- 2}

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2.186 \times 10^{4} m s^{- 1}

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Solution

The correct option is B $2.186 \times 10^{6} m s^{- 1}$
Velocity of electron in $n^{t h}$ orbit $= 2.186 \times 10^{6} \times \frac{1}{n}$ $m / s$
$∴$ Velocity in ground state $1^{s t}$ orbit $= 2.186 \times 10^{6}$ $m / s$ .

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The speed of an electron in the ground state of hydrogen atom is:

The correct option is B 2.186×106ms−1Velocity of electron in nth orbit =2.186×106×1n m/s∴ Velocity in ground state 1st orbit =2.186×106 m/s.

The correct option is B $2.186 \times 10^{6} m s^{- 1}$
Velocity of electron in $n^{t h}$ orbit $= 2.186 \times 10^{6} \times \frac{1}{n}$ $m / s$
$∴$ Velocity in ground state $1^{s t}$ orbit $= 2.186 \times 10^{6}$ $m / s$ .