Framing the equation: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
Let the speed of express train be x km/h Then the speed of ordinary train will be (x-12) km/h.
Time taken by express train =240xh
Time taken by ordinary train =240x−12h
According to the question,
240x−12−240x=1⇒240x−240x+2880(x−12)(x)=1
⇒2880=x2−12x⇒x2−60x+48x−2880=0⇒x(x−60)+48(x−60)=0⇒(x−60)(x+48)=0
Either x - 60 = 0 or x + 48 = 0
⇒x=60 or x = −48
Since the speed cannot be negative, so we reject x = −48.
Hence the speed of the express train is 60 km/h.