The speed of body of mass 4 kg increases from 2 metre per second to 4 metre per second in certain time interval find the increase in kinetic energy a body

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Solution

m=4kg
v1=2m/s
v2=4m/s

K.E1=1/2mv1^2

=1/242^2

=8 joule

K.E2=1/2mv2^2

=1/244^2

=32 joule

increase in kinetic energy = K.E2-K.E1 = 32-8 = 24 joule

the increase in K.E is 24 joule

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The speed of body of mass 4 kg increases from 2 metre per second to 4 metre per second in certain time interval find the increase in kinetic energy a body

m=4kg v1=2m/s v2=4m/s K.E1=1/2*m*v1^2 =1/2*4*2^2 =8 joule K.E2=1/2*m*v2^2 =1/2*4*4^2 =32 joule increase in kinetic energy = K.E2-K.E1 = 32-8 = 24 joule the increase in K.E is 24 joule

m=4kg
v1=2m/s
v2=4m/s

K.E1=1/2mv1^2

=1/242^2

=8 joule

K.E2=1/2mv2^2

=1/244^2

=32 joule

increase in kinetic energy = K.E2-K.E1 = 32-8 = 24 joule

the increase in K.E is 24 joule