The correct option is A [G12h12c−52]
Here, [c] = LT−1
[G]=M−1L3T−2
[h]=M1L2T−1
Let, t∝cxGyhz
By substituting the dimensions of each quantity in both the sides,
T=(LT−1)x(M−1L3T−2)y(ML2T−1)z
By equating the power of M, L, T in both the sides,
−y+z=0
x+3y+2z=0
−x−2y−z=1
By solving the above equation,
We get, x=−52,y=12,z=12
So, [t]=[c−52G12h12]