The speed of sound in air is $350 m / s$ . the fundamental frequency of the open pipe of length $50 c m$ is :

100 H z

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250 H z

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350 H z

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400 H z

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Solution

The correct option is D $350 H z$
Fundamental frequency of an open organ pipe is given by ,
$n_{1} = v / λ = v / 2 l$ ,
where $v =$ speed of sound in air ( $= 350 m / s, g i v e n$ ),
$λ =$ wavelength ,
$l =$ length of organ pipe ( $= 50 c m = 0.50 m$ , given) ,
therefore , $n_{1} = 350 / (2 \times 0.50) = 350 H z$

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The speed of sound in air is 350m/s. the fundamental frequency of the open pipe of length 50cm is :

The correct option is D 350HzFundamental frequency of an open organ pipe is given by , n1=v/λ=v/2l ,where v=speed of sound in air (=350m/s,given), λ= wavelength , l= length of organ pipe (=50cm=0.50m , given) ,therefore , n1=350/(2×0.50)=350Hz

The speed of sound in air is $350 m / s$ . the fundamental frequency of the open pipe of length $50 c m$ is :