The speed of sound in oxygen $(O_{2})$ at a certain temperature is $460 m s^{- 1}$ The speed of sound in helium ( $H e$ ) at the same temperature will be :
(assume both gases to be ideal)

1419 m s^{- 1}

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710 m s^{- 1}

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720 m s^{- 1}

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230 m s^{- 1}

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Solution

The correct option is A $1419 m s^{- 1}$
Velocity of sound in gases $= \sqrt{\frac{γ R T}{M}}$
For $O_{2},$ $γ = \frac{7}{5}$
For $H e,$ $γ = \frac{5}{3}$
$\frac{v_{H e}}{v_{O_{2}}} = \sqrt{\frac{γ_{H e} \times M_{O_{2}}}{γ_{O_{2}} \times M_{H e}}}$
Solving we get
$v_{H e} = 1419 m s^{- 1}$

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Similar questions

Q. The speed of sound in oxygen

(O_{2})

at a certain temperature is

460 m / s

. The speed in helium

(H e)

at the same temperature will be [assume both gases to be ideal]

Q. The velocity of sound in air at a certain temperature is

350 m s^{- 1}

. What will be the velocity of sound in helium at the same temperature?

(γ_{a i r} = \frac{7}{5})

[molecular mass of air = 29, molecular mass of helium = 4]

At what temperature will the speed of sound in hydrogen be the same as in oxygen at 100 $^{\circ}$ C? Molar masses of oxygen and hydrogen are in the ratio 16:1.

Q. At what temperature the speed of sound in nitrogen will be equal to the speed of sound in oxygen at

55^{\circ} C

Q. At what temperature will the speed of sound in a monoatomic gas be the same as in a diatomic gas at

127^{\circ} C

? Molar mass of diatomic and monoatomic gases are in the ratio

16 : 1

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The speed of sound in oxygen (O2) at a certain temperature is 460 ms−1 The speed of sound in helium (He) at the same temperature will be :(assume both gases to be ideal)

The correct option is A 1419 ms−1Velocity of sound in gases=√γRTMFor O2, γ=75For He, γ=53vHevO2=√γHe×MO2γO2×MHeSolving we getvHe=1419ms−1

The speed of sound in oxygen $(O_{2})$ at a certain temperature is $460 m s^{- 1}$ The speed of sound in helium ( $H e$ ) at the same temperature will be :
(assume both gases to be ideal)

The correct option is A $1419 m s^{- 1}$
Velocity of sound in gases $= \sqrt{\frac{γ R T}{M}}$
For $O_{2},$ $γ = \frac{7}{5}$
For $H e,$ $γ = \frac{5}{3}$
$\frac{v_{H e}}{v_{O_{2}}} = \sqrt{\frac{γ_{H e} \times M_{O_{2}}}{γ_{O_{2}} \times M_{H e}}}$
Solving we get
$v_{H e} = 1419 m s^{- 1}$