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Question

The speed of the trolley when the man jumps off the trolley is

A
2
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B
4
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C
8
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D
16
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Solution

The correct option is B 8
Mass of trolley=m=40kg
Mass of the man=M=80kg
Since no external force acts in horizontal direction, the conservation of momentum along the direction holds.
Hence (M+m)v0=Mvman+mvtrolley
(80+40)2=(80)(1)+(40v)
v=8m/s

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