The speed-time graph of a particle moving along a fixed direction is shown in Fig. Obtain the distance traversed by the particle between time t = 0 s to 10 s.

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Solution

Distance travelled by the particle = Area under the given graph
$= \frac{1}{2} \times (10 - 0) \times (12 - 0) = 60 m$
Average speed = $\frac{Distance}{Time} = \frac{60}{10} = 6 m / s$

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The speed-time graph of a particle moving along a fixed direction is shown in Fig. Obtain the distance traversed by the particle between time t = 0 s to 10 s.

Distance travelled by the particle = Area under the given graph=12×(10−0)×(12−0)=60 mAverage speed = Distance Time=6010=6m/s

Distance travelled by the particle = Area under the given graph
$= \frac{1}{2} \times (10 - 0) \times (12 - 0) = 60 m$
Average speed = $\frac{Distance}{Time} = \frac{60}{10} = 6 m / s$