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Question

The speed v of a car moving on a straight road changes according to equation, v2=a+bx, where a and b are positive constants. Then, the magnitude of acceleration in the course of such motion: (x is the distance travelled) :

A
Increases
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B
Decreases
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C
Stays constant
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D
First decreases and then increases
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Solution

The correct option is C Stays constant
v=a+bx
We know that,
a=vdvdx
=a+bx×b2a+bx
=b2 (constant)
Alternate solution:
v2=a+bx
Comparing with
v2=u2+2as
2a=ba=b2 (constant).

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