The speed v of a car moving on a straight road changes according to equation, v2=a+bx, where a and b are positive constants. Then, the magnitude of acceleration in the course of such motion: (x is the distance travelled) :
A
Increases
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B
Decreases
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C
Stays constant
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D
First decreases and then increases
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Solution
The correct option is C Stays constant v=√a+bx
We know that, a=vdvdx =√a+bx×b2√a+bx =b2 (constant)
Alternate solution: v2=a+bx
Comparing with v2=u2+2as ⇒2a=b⇒a=b2 (constant).