CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

The speed with which the earth have to rotate on its axis so that a person on the equator would weight (3/5)th as much as presentwill be. [Take a equilateral radius of earth =6400 km]

A
3.28×104rad/sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7.28×103rad/sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.28×103rad/sec
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
7.826×104rad/sec
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 3.28×103rad/sec
The apparent weight of person on the equal (latitude λ=0) is given by
ω=WmRω2
Here ω=(3/5)w=(3/5)mg [ω=mg]
or mRω2=mg(3/5)mg=(25)mg
or ω2=2g5R
ω=2g5R
Here, g=9.8ms2
and R=6400km=6400×103m
ω=(25×9.86400×103)rads1
=7.82×104rads1.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integrating Solids into the Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon