The sphere of diameter 0-02 m falls in a fluid of kinematic viscosity of 10 stokes with the terminal velocity of 0-02 m-s- What is the value of the coefficient of drag on the falling sphere-

Reynold's number is given by, R_e = VDv=0.02× 0.02 10×10^ 4 R_e = 0.4 The approximate solution due to Stoke's law is valid for R_e lt; 0.5. So, coefficie ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Fluid Mechanics

Drag on a Sphere

The sphere of...

Question

The sphere of diameter 0.02 m falls in a fluid of kinematic viscosity of 10 stokes with a terminal velocity of 0.02 m/s. What is the value of the coefficient of drag on the falling sphere?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 60
Reynold's number is given by,

$R_{e} = \frac{V D}{v} = \frac{0.02 \times 0.02}{10 \times 10^{- 4}}$

$R_{e} = 0.4$

The approximate solution due to Stoke's law is valid for $R_{e}$ < 0.5.

So, coefficient of drag,

$C_{D} = \frac{24}{R_{e}} = \frac{24}{0.4} = 60$

Suggest Corrections

Similar questions

Q. In the Stoke's experiment of falling sphere. if is found that a sphere of 5 mm diameter falls in a liquid with terminal velocity 20 mm/s giving a drag coefficient of 240. The ratio of specific gravities is 2.85. Which one of the following is the kinematic viscosity of the liquid in stokes?

Q. A solid sphere, of radius R acquires a terminal velocity

v_{1}

when falling (due to gravity) through a viscous fluid having a coefficient of viscosity

η

. The sphere is broken into 27 identical solid spheres. If each of these spheres acquires a terminal velocity

v_{2}

, when falling through the same fluid, the ratio

(\frac{v_{1}}{v_{2}})

equals:

Q. When small sphere falls freely in stokes range through a water column, which of the following statement are correct?
1. Viscosity, surface tension and gravitational forces act on the sphere.
2. There is no turbulence possible in the wake of the falling sphere.
3. Drag coefficient,

C_{d} = R / 24

, where R is Reynolds number.
4.Proximity of the boundary moderates the drag and lift coefficients.

Q. Water having kinematic viscosity of 0.01 stokes flows at a velocity of 2 m/sec in a pipe of 15 cm diameter. For dynamic similarity, the velocity of oil of kinematic viscosity 0.03 stoke in a pipe of same diameter will be

Q. A metal sphere of diameter

7 c m

falls through a liquid of coefficient of viscosity

0.8 P a . s

. When its velocity is

20 c m . s^{- 1}

the viscous force acting on it is nearly ----

N .

Join BYJU'S Learning Program

The sphere of diameter 0.02 m falls in a fluid of kinematic viscosity of 10 stokes with a terminal velocity of 0.02 m/s. What is the value of the coefficient of drag on the falling sphere?

The correct option is B 60Reynold's number is given by, Re=VDv=0.02×0.0210×10−4 Re=0.4 The approximate solution due to Stoke's law is valid for Re < 0.5. So, coefficient of drag, CD=24Re=240.4=60

The correct option is B 60
Reynold's number is given by,

$R_{e} = \frac{V D}{v} = \frac{0.02 \times 0.02}{10 \times 10^{- 4}}$

$R_{e} = 0.4$

The approximate solution due to Stoke's law is valid for $R_{e}$ < 0.5.

So, coefficient of drag,

$C_{D} = \frac{24}{R_{e}} = \frac{24}{0.4} = 60$