The spin angular momentum of an electron is given by:
A
{√(s(s+1)}h2π
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B
sh2π
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C
√34sh2π
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D
h4π
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Solution
The correct option is A{√(s(s+1)}h2π The magnitude of spin angular momentum is given by: {√(s(s+1)}h2π.
For a single electron, s=±12 s=+12 √12(12+1)h2π. =√32h2π