Question

The spin magnetic moment of cobalt in the compound $K_2\left[Co{\left(SCN\right)}_4\right]$ is :

• A. $\sqrt{3}$ BM
• B. $\sqrt{8}$ BM
• C. $\sqrt{15}$ BM
• D. $\sqrt{24}$ BM

Answer 1

The correct option is C $\sqrt{15}$ BM

$K_2\left[Co{\left(SCN\right)}_4\right]$
$C{o}^{+2},d^7$ configuration so it will have 3 unpaired electron and magnetic moment $\mu =\sqrt{n(n+2)}$ where n is no. of unpaired electron.
$\mu =\sqrt{3(3+2)}=\sqrt{15}$ BM