The “spin-only” magnetic moment, in units of Bohr magnetron (μB), of Ni2+in aqueous solution would be
A
4.9
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B
1.73
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C
2.84
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Solution
The correct option is C 2.84 Ni2+in aqueous solution exists as [Ni(H2O)6]2+. It has sp3d2 hybridisation as Ni2+→3d84s0 ∴No. of unpaired electron = 2 ∴μs=√n(n+2)=√2(2+2)=2.84