Question

The spin only magnetic moment of a divalent ion in aqueous solution (atomic number 29) is ____ BM
.

Answer 1

${}_{29}C{u}^{2+}\to [Ar{]}^{18}3d^9$


Number of unpaired electron = 1
Magnetic moment =$\mu =\sqrt{n(n+2)}$
$\mu =\sqrt{\left(1\right)(1+2)}=\sqrt{3}BM$
$\mu =1.73BM$