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Question

The spin only magnetic moment of [MnBr4]2 is 5.9B.M Geometry of the complex ion is:

A
Tetrahedral
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B
Octahedral
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C
Squareplanae
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D
Pentagonalpyramidal
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Solution

The correct option is A Tetrahedral
The oxidation state of Mn in [MnBr4]2 is +2 and since its magnetic moment is 5.92 BM This impliesn(n+2) = 5.92 BM, n=5. Hence Mn has 5 unpaired electrons. As Br is a weak field ligand, therefore, this also implies that the pairing of electrons will not take place and electronic configuration of Mn will be 3d54s0.Now, 4s and 4p orbital of Mn participate in hybridization and the hybridization is sp3 and the geometry will be tetrahedral.

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