The spin only magnetic moment of $[M n B r_{4}]^{2 -}$ is $5.9 B M$ . Predict the geometry of the complex ion?

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Solution

Magnetic moment $= \sqrt{n (n + 2)} = 5.9$ (given)
$∴ 35 = n (n + 2)$ or $n = 5$

Magnetic moment is $5.9 B M$ means unpaired electrons are $5$
Bromine is a type of weak field ligand, so back pairing will not occur.
So, the geometry of the compound is tetrahedral and hybridisation is $s p^{3}$

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