Question

The spin only magnetic moment of $X^{n+}(Z=26)is\sqrt{24}$ B.M. Hence the number of unpaired electrons and the value of n respectively are:

• A. 4, 2
• B. 2, 4
• C. 3, 1
• D. 0, 2

Answer 1

The correct option is A 4, 2

$\sqrt{24}=\sqrt{n(n+2)}$
$24=n^2+2n$
$n^2+2n-24=0$
$n^2+6n-4n-24=0$
$(n+6)(n-4)=0$
$n=4$
No. of unpaired electrons = 4 and the charge on X is 2.