The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is:
A
0
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B
2.84
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C
4.90
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D
5.92
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Solution
The correct option is A0 As CO is strong field ligand,in Cr(CO)6, d2sp3 is the hybridisation and 3d6 has no unpaired electrons. So it has zero magnetic moment.