The spin only magnetic momentum of trivalent titanium cation is

$1.6 \times 10^{- 23} J T^{- 1}$

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$2.62 \times 10^{- 23} J T^{- 1}$

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$2.59 \times 10^{- 23} J T^{- 1}$

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$4.54 \times 10^{- 23} J T^{- 1}$

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Solution

The correct option is A
$1.6 \times 10^{- 23} J T^{- 1}$

$T i^{3 +}$ has configuration $3 d^{1} 4 s^{0}$ Number of unpaired electrons in $= \sqrt{n (n + 2)} = 1.73 B M$
One $B M = 9.273 \times 10^{- 24} J T^{- 1}$

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