The splash of sound was heard $5.35 s$ after dropping a stone into a well $122.5 m$ deep. The velocity of sound in air is:

350 c m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

350 m / s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

392 c m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0 c m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $350 m / s$
Time taken by the stone to reach the water,

$t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{2 \times 122.5}{9.8}} = 5 s e c$

So, the remaining time $= 5.35 - 5 = 0.35 s e c$

$0.35 s e c$ was taken by sound to travel $122.5 m$

Hence, speed $= \frac{122.5}{0.35} = 350 m / s$

Suggest Corrections

Similar questions

44.1 m

3.13 s

g = 9.8 m / s^{2}

2.05 s

19.6 m

[g = 10 m s^{- 2}]

45 m

3.125 s

(g = 10 m / s^{2})

Join BYJU'S Learning Program