The spontaneous cell reaction (i.e., redox reaction) in galvanic cell is derived by:

reduction reaction at right electrode - reduction reaction at left electrode

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oxidation reaction at left electrode + reduction reaction at right electrode

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reduction reaction at right electrode + reduction reaction at left electrode

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oxidation reaction at left electrode - oxidation reaction at right electrode

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Solution

The correct options are
A reduction reaction at right electrode - reduction reaction at left electrode
B oxidation reaction at left electrode + reduction reaction at right electrode
D oxidation reaction at left electrode - oxidation reaction at right electrode

We know that in any Galvanic Cell, Oxidation occurs at Anode (Left Hand Electrode) and Reduction occurs at Cathode (Right Hand Electrode).

Hence, EMF of the Cell will be given as:

$E_{c e l l}^{0}$ = $E_{S R P, c a t h o d e}^{0}$ + $E_{S O P, a n o d e}^{0}$

$E_{c e l l}^{0}$ = $E_{S R P, c a t h o d e}^{0}$ - $E_{S R P, a n o d e}^{0}$

$E_{c e l l}^{0}$ = $E_{S O P, a n o d e}^{0}$ - $E_{S O P, c a t h o d e}^{0}$
Hence, option $C$ is incorrect and all other options are the answers.

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Similar questions

Q. A cell consists of two hydrogen electrodes, the negative electrode has

[H^{+}] = 10^{- 7} M

. Find the minimum pH of the other electrode at which, the cell reaction will be spontaneous.
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Q. (a) Following reactions occur at cathode during the electrolysis of aqueous sodium chloride solution:

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H^{+} (a q) + e^{-} ⟶ \frac{1}{2} H_{2} (g) E^{0} = 0.00 V

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Q. Depict the galvanic cell in which the reaction

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takes place. Further show individual reaction at each electrode.

Depict the galvanic cell in which the reaction $Z n (s) + 2 A g^{+} (a q) ⟶ Z n^{2 +} (a q) + 2 A g (s)$ takes place, further show:
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Individual reaction at each electrode.

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