The spot speed (expressed in km/hr) observed at a road section are 66, 62, 45, 79, 32, 51, 56, 60, 53 and 49. The median speed expressed in km/hr is .
[Note Answer with one decimal accuracy]

54.5

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Solution

The correct option is A 54.5

On arranging spot speeds in ascending order we have 32, 39, 45, 51, 53, 56, 60, 62, 66, 79

Here n = 10

$M e d i a n s p e e d = \frac{\frac{n^{t h}}{2} + {(\frac{n}{2} + 1)}^{t h}}{2}$
=average of 5th and 6th observation

$= \frac{53 + 56}{2} = 54.5 K m / h r$

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The spot speed (expressed in km/hr) observed at a road section are 66, 62, 45, 79, 32, 51, 56, 60, 53 and 49. The median speed expressed in km/hr is . [Note Answer with one decimal accuracy] 54.5

The correct option is A 54.5 On arranging spot speeds in ascending order we have 32, 39, 45, 51, 53, 56, 60, 62, 66, 79 Here n = 10 Median speed=nth2+(n2+1)th2 =average of 5th and 6th observation =53+562=54.5Km/hr

The spot speed (expressed in km/hr) observed at a road section are 66, 62, 45, 79, 32, 51, 56, 60, 53 and 49. The median speed expressed in km/hr is .
[Note Answer with one decimal accuracy]

54.5

The correct option is A 54.5

On arranging spot speeds in ascending order we have 32, 39, 45, 51, 53, 56, 60, 62, 66, 79

Here n = 10

$M e d i a n s p e e d = \frac{\frac{n^{t h}}{2} + {(\frac{n}{2} + 1)}^{t h}}{2}$
=average of 5th and 6th observation

$= \frac{53 + 56}{2} = 54.5 K m / h r$