The spring is compressed by a distance a and released. The block again comes to rest when the spring is elongated by a distance b. During this process:
A
work done by the spring on the block = 12k(a−b)2
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B
work done by the spring on the block = 12k(a2+b2)
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C
co-efficient of friction = k(a−b)2mg
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D
co-efficient of friction = k(a+b)2mg
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Solution
The correct options are A work done by the spring on the block = 12k(a−b)2 C co-efficient of friction = k(a−b)2mg