The square of $0.02$ is

Open in App

Solution

$0.02 = 2 \times 10^{- 2}$
${0.02}^{2} = 2^{2} \times (10^{- 2})^{2} = 0.0004$

Suggest Corrections

Similar questions

Q. Find the square root of

0.02

Q. The expression

(11.98 \times 11.98 + 11.98 \times x + 0.02 \times 0.02)

will be a perfect square for

x

equal to:

Four chargers $q_{1} = - 0.02 μ C$ , $q_{2} = + 0.04 μ C$ , $q_{3} = + 0.02 μ C$ , and $q_{4} = - 0.04 μ C$ are at the four corners of a square of side $9 c m$ . Then the potential at the centre of the square is :

Q. The area of square is

9 s q c m s

and the error in its is

0.02 s q . c m

The percentage error in the measurement of the length of the diagonal of the square is

Q. The length of side of square is 2.00 cm. The perimeter of the square is
a.) (8.00 ± 0.01) cm
b.) (8.00 ± 0.02) cm
c.) (8.00 ± 0.03) cm
d.) (8.00 ± 0.04) cm

Join BYJU'S Learning Program

The square of 0.02 is

0.02=2×10−20.022=22×(10−2)2=0.0004

The square of $0.02$ is

$0.02 = 2 \times 10^{- 2}$
${0.02}^{2} = 2^{2} \times (10^{- 2})^{2} = 0.0004$