The square of (2 $x$ -1) is equal to 5. What is $x$ ?

x= (1 + √5)/2

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x= (-1 - √5)/2

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x= (-1 + √5)/2

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x= (1 + √6)/2

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Solution

The correct option is A
x= (1 + √5)/2

$(2 x - 1)^{2}$ = 5

$(2 x - 1) = \pm \sqrt{5}$

$2 x = \pm \sqrt{5} + 1$

$x = (1 \pm \sqrt{5}) 2$

$x$ = $\frac{1 + \sqrt{5}}{2}$ or $x$ = $\frac{1 - \sqrt{5}}{2}$

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