The square of a natural number subtracted from its cube is 48. The number is:

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 4
Let the number be x.
$x^{3} - x^{2} = 48$
$x^{2} (x - 1) = 48 = 4^{2} (4 - 1)$
$∴ x = 4$

Suggest Corrections

Similar questions

Find the number whose square is the sum of the cube of the first 5 natural numbers.

The square root of a natural number is equal to K times its cube root. The number must be

If a number is both perfect square and perfect cube, then it will have a sixth root which is a natural number.

Join BYJU'S Learning Program