The square of a number is decreased by 15 which is twice the original number. What are the numbers?

8, 7

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9, 6

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2, -7

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5, -3

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Solution

The correct option is D
5, -3

Let the number be x

Given, $x^{2} - 15 = 2 x$

$\Rightarrow$ $x^{2} - 2 x - 15 = 0$

$\Rightarrow$ $x^{2} - 5 x + 3 x - 15 = 0$

$\Rightarrow$ $x (x - 5) + 3 (x - 5) = 0$

$(x - 5) (x + 3) = 0$

$\Rightarrow$ $x = 5 a n d x = - 3$

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