The square of a positive integer CANNOT be of the form (k is an integer): (a) 3k + 1 (b) 4k + 2 (c) 5k + 1

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Solution

The way to solve this is simply assigning integers to k
for a)3k+1
If k=1 it becomes for which is a square of 2
Likewise in C)5k+1
Assigning k=1,2,3..
At 3, 5*3+1=16 which is square of 4. Hence the answer is b which is 4k+2

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The square of a positive integer cannot be a form/(, K is an integer) :

(a) 3 k + 1

(b) 4 k + 2

(d) 5 k + 4

Good evening,

My doubt is

The square of a positive integer CANNOT be of the form (k is an integer):

(a) 3k + 1 (b) 4k + 2 (c) 5k + 1 (d) 5k + 4

The square of a positive integer CANNOT be of the form ( k is an integer) : ( a ) 3k + 1. ( b ) 4K +2. ( c) 5k +1. ( d ) 5k + 4.

k, 2 k, 3 k, 4 k

5 k

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