Question

The square of an odd number is even.
If true then enter $1$ and if false then enter $0$

Answer 1

Odd number is of the form $2n+1$
Square of odd $=(2n+1{)}^2$

$=4n^2+4n+1=2(2n^2+2n)+1$
It is of the form $2K+1$.

Hence square of an odd number is always odd.

Therefore the given statement is false and correct answer is $0$.