The square of the magnitude of the vector -3-4-5k- will be

As discussed if a vector is expressed in terms of î, nbsp;ĵ and k̂ nbsp;then its nbsp;magnitude is given nbsp;by √((coeff of î)^2+(coeff of ĵ)^2+(coeff ...

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Standard XII

Mathematics

Representation of Vectors

The square of...

Question

The square of the magnitude of the vector $3^i + 4^j + 5^k$ will be __

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Solution

As discussed if a vector is expressed in terms of $^i,^j$ and $^k$ then its magnitude is given by $\sqrt{(coeff of^i)^{2} + (coeff of^j)^{2} + (coeff of^k)^{2}}$
So for $3^i + 4^j + 5^k$
Magnitude $= \sqrt{3^{2} + 4^{2} + 5^{2}}$
$= \sqrt{50}$
Square of magnitude $= {(\sqrt{50})}^{2} = 50$

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The square of the magnitude of the vector ​3^i+4^j+5^k will be __

As discussed if a vector is expressed in terms of ^i,^j and ^k then its magnitude is given by √(coeff of ^i)2+(coeff of ^j)2+(coeff of ^k)2 So for 3^i+4^j+5^k Magnitude =√32+42+52 =√50 Square of magnitude =(√50)2=50

The square of the magnitude of the vector $3^i + 4^j + 5^k$ will be __

As discussed if a vector is expressed in terms of $^i,^j$ and $^k$ then its magnitude is given by $\sqrt{(coeff of^i)^{2} + (coeff of^j)^{2} + (coeff of^k)^{2}}$
So for $3^i + 4^j + 5^k$
Magnitude $= \sqrt{3^{2} + 4^{2} + 5^{2}}$
$= \sqrt{50}$
Square of magnitude $= {(\sqrt{50})}^{2} = 50$