Question

The square planar shape is ____

• A. $sp$
• B. $ds{p}^3$
• C. $ds{p}^2$
• D. $s{p}^3$

Answer 1

The correct option is C $ds{p}^2$

The correct answer is 1. Hybridisation present is $ds{p}^2$ and has square planar shape.

One example is $\left[Ni\right(CN{)}_6{]}^{4-}$ is square planar. $N{i}^{2+}$ has an electron configuration of [Ar] $3d^8$ and its orbital diagram is (in this case it is the excited state of $N{i}^{2+}$) so the $3d,4s,and4p$ orbitals are available for hybridization, which results in the hybridization $ds{p}^2$.