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Algebraic Expressions

The square ro...

Question

The square root of $49 {(x^{2} - 2 x y + y^{2})}^{2}$ is:

7 | x - y |

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7 (x + y) (x - y)

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7 {(x + y)}^{2}

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7 {(x - y)}^{2}

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Solution

The correct option is C $7 {(x - y)}^{2}$
Given equation is $49 (x^{2} - 2 x y + y^{2})^{2}$

$= 7^{2} [(x - y)^{2}]^{2}$ ..... $[$ Since $(a - b)^{2} = a^{2} - 2 a b + b^{2}]$

Taking square root, we get

$= 7 (x - y)^{2}$

Hence, option D is correct.

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The square root of 49(x2−2xy+y2)2 is:

The correct option is C 7(x−y)2Given equation is 49(x2−2xy+y2)2=72[(x−y)2]2 ..... [ Since (a−b)2=a2−2ab+b2]Taking square root, we get=7(x−y)2Hence, option D is correct.

The square root of $49 {(x^{2} - 2 x y + y^{2})}^{2}$ is:

The correct option is C $7 {(x - y)}^{2}$
Given equation is $49 (x^{2} - 2 x y + y^{2})^{2}$

$= 7^{2} [(x - y)^{2}]^{2}$ ..... $[$ Since $(a - b)^{2} = a^{2} - 2 a b + b^{2}]$

Taking square root, we get

$= 7 (x - y)^{2}$

Hence, option D is correct.