Question

The square root of 64 divided by the cube root of 64 is

• A. 64
• B. 2
• C. $\frac{1}{2}$
• D. 64^{$frac23$}

Answer 1

Answer: (B)

$\sqrt{64}÷\sqrt[3]{364}=\sqrt{8^2}÷\sqrt[3]{34^3}\Rightarrow (8^2{)}^{\frac{1}{2}}÷(4^3{)}^{\frac{1}{3}}=8^{2\times \frac{1}{2}}÷4^{3\times \frac{1}{3}}=8÷4=\frac{8}{4}=2$