Question

The square-root of $\frac{(0.75{)}^3}{1-\left(0.75\right)}+\left(0.75+(0.75{)}^2+1\right)$ is$?$

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

The correct option is B $2$

We have, $a=\sqrt{\frac{{\left(0.75\right)}^3}{1-0.75}+(0.75+{\left(0.75\right)}^2+1)}$

$=\sqrt{\frac{{\left(0.75\right)}^3+(1-0.75)(0.75+{\left(0.75\right)}^2+1)}{1-0.75}}$

$=\sqrt{\frac{{\left(0.75\right)}^3+1-{\left(0.75\right)}^3}{1-0.75}}=\sqrt{\frac{1}{0.25}}$

$=\sqrt{4}$

Therefore, $a=2$.

Therefore, the correct option is $B$