The square root of $(272^{2} - 128^{2})$ is :

144

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200

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240

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256

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249

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Solution

The correct option is C
240

$\sqrt{{(272)}^{2} - {(128)}^{2} =} \sqrt{(272 + 128) (272 - 128)} = \sqrt{400 \times 144} = \sqrt{57600} = 240.$

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128² - 127² =

If square root of 5=2.236 and square root of 10=3.162 then what is the value of square root of 10 minus square root of 5 diveded by square root of 2.

The rationalising factor of 4 square root 5 .

Option

A. Square root 5

B. 3 square root 5

C. 4 square root 125

Prove that square root of 3+ square root of 5 is irrational

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