The square root of $x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 1$ using the division method is equal to $x^{2} - x + 1$ .

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
Hence, the square root of $x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 1$ is $x^{2} - x + 1$ .

Suggest Corrections

Similar questions

x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 1

x^{4} + 2 x^{3} - 3 x^{2} + 2 x - 1

x^{4} - 6 x^{3} + 19 x^{2} - 30 x + 25

x^{4} + 4 x^{3} + 8 x^{2} - 8 x + 4

(x^{2} + x + 1)

(x^{4} + x^{2} + 1)

Join BYJU'S Learning Program