The square roots of two natural numbers x, y are 25 and 12. It is given that x < y. Choose the correct options.

$\sqrt{x}$ = 12

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$\sqrt{x}$ = 25

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$\sqrt{y}$ = 12

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$\sqrt{y}$ = 25

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Solution

The correct options are
A
$\sqrt{x}$ = 12

D
$\sqrt{y}$ = 25

Square root of a smaller number will be less than than the square root of the larger number.
$x < y ⟹ \sqrt{x} < \sqrt{y}$
$12 < 25 \Rightarrow \sqrt{x} = 12$ and $\sqrt{y} = 25$

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The square roots of two natural numbers x, y are 25 and 12. It is given that x < y. Choose the correct options.

The correct options are A √x = 12 D √y = 25 Square root of a smaller number will be less than than the square root of the larger number. x<y⟹√x<√y 12<25⇒√x=12 and √y=25

The correct options are
A
$\sqrt{x}$ = 12

D
$\sqrt{y}$ = 25

Square root of a smaller number will be less than than the square root of the larger number.
$x < y ⟹ \sqrt{x} < \sqrt{y}$
$12 < 25 \Rightarrow \sqrt{x} = 12$ and $\sqrt{y} = 25$