The stabilities of coordination compounds containing the ions $C u^{2 +}, N i^{2 +}, C o^{2 +}, F e^{2 +}$ and $M n^{2 +}$ follow the order:

M n^{2 +} > F e^{2 +} > C o^{2 +} > N i^{2 +} > C u^{2 +}

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N i^{2 +} > C u^{2 +} > F e^{2 +} > C o^{2 +} > M n^{2 +}

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C u^{2 +} > N i^{2 +} > C o^{2 +} > F e^{2 +} > M n^{2 +}

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F e^{2 +} > M n^{2 +} > N i^{2 +} > C o^{2 +} > C u^{2 +}

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Solution

The correct option is C $C u^{2 +} > N i^{2 +} > C o^{2 +} > F e^{2 +} > M n^{2 +}$
Stability is nothing but the capability of complex formation or complex formation tendency.

The stabilities follow the Irwing Williams order given by $C u^{2 +} > N i^{2 +} > C o^{2 +} > F e^{2 +} > M n^{2 +}$ .

It is important to remember this order as states that the bipositive ions of the 3d series become more stable from right to left.

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Similar questions

M^{2 +}

Z n^{2 +} > S c^{2 +} = C u^{2 +} > T i^{2 +} = N i^{2 +} > V^{2 +} = C o^{2 +} > C r^{2 +} = F e^{2 +} > M n^{2 +}

Write down the number of 3d electrons in each of the following ions:

Ti²⁺, V²⁺, Cr³⁺, Mn²⁺, Fe²⁺, Fe³⁺, CO²⁺, Ni²⁺ and Cu²⁺.

Indicate how would you expect the five 3d orbitals to be occupied for these hydrated ions (octahedral).

V^{2 +} < C r^{2 +} < M n^{2} < F e^{2 +}

N i^{2 +} < C o^{2 +} < F e^{2 +} < M n^{2 +}

C o^{3 +} < F e^{3 +} < C r^{3 +} < S c^{3 +}

S c < T i < C r < M n

Magnetic moment of which ion is 2.88 BM ?

H_{2} S

{M n}^{2 +}, {N i}^{2 +}, {C u}^{2 +}, {H g}^{2 +}

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