The stability of carbanions in the following i RC - Ciiiii R 2 C - CHiv R 3 C - CH 2is in the order ofA- i - ii - iii - ivB- ii - iii - iv - i C- i - iii - ii - iv D- iv - ii - iii - i

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Carbanion

The stability...

Question

The stability of carbanions in the following

i) $R C \equiv ⊖ C$

ii)

iii) $R_{2} C = ⊖ C H$

iv) $R_{3} C - ⊖ C H_{2}$

is in the order of

(i) > (ii) > (iii) > (iv)

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(ii) > (iii) > (iv) > (i)

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(iv) > (ii) > (iii) > (i)

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(i) > (iii) > (ii) > (iv)

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Solution

The correct option is A
(i) > (ii) > (iii) > (iv)

The carbanion with more s-character is more stable. Thus, the order of stability is

$R C \equiv ⊖ C > C_{6} H_{5}^{⊖} > R_{2} C = ⊖ C H > R_{3} C - ⊖ C H_{2}$

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The stability of carbanions in the following i) RC≡⊖C ii) iii) R2C=⊖CH iv) R3C−⊖CH2 is in the order of

The correct option is A (i) > (ii) > (iii) > (iv) The carbanion with more s-character is more stable. Thus, the order of stability is RC≡⊖C>C6H⊖5>R2C=⊖CH>R3C−⊖CH2

The stability of carbanions in the following

i) $R C \equiv ⊖ C$

ii)

iii) $R_{2} C = ⊖ C H$

iv) $R_{3} C - ⊖ C H_{2}$

is in the order of

The correct option is A
(i) > (ii) > (iii) > (iv)

The carbanion with more s-character is more stable. Thus, the order of stability is

$R C \equiv ⊖ C > C_{6} H_{5}^{⊖} > R_{2} C = ⊖ C H > R_{3} C - ⊖ C H_{2}$