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Question

The stability of carbanions in the following

i) RCC

ii)

iii) R2C=CH

iv) R3CCH2

is in the order of


A

(i) > (ii) > (iii) > (iv)

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B

(ii) > (iii) > (iv) > (i)

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C

(iv) > (ii) > (iii) > (i)

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D

(i) > (iii) > (ii) > (iv)

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Solution

The correct option is A

(i) > (ii) > (iii) > (iv)


The carbanion with more s-character is more stable. Thus, the order of stability is

RCC>C6H5>R2C=CH>R3CCH2


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