The stability of $M e_{2} C = C H_{2}$ is more than that of $M e C H_{2} C H = C H_{2}$ due to:

Inductive effect of the Me group

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resonance effect of the Me group

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Hyperconjugative effect of the Me group.

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resonance as well as inductive effect of the Me group.

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Solution

The correct option is C
Hyperconjugative effect of the Me group.

If I say,

$\to$ A more substituted alkene is more stable. You will ask me why ?

Let's find out.

Stabilities of alkenes is again due to hyper conjugation.

For example,

(A)

+11 more hyperconjugative structures

(B)

+8 more hyperconjugative structures

(A) and (B) show 13 and 10 H.C. structures respectively. So (A) is more stable than (B). conversely, (B) is more reactive than (A).

Therefore, $M e_{2} C = C H_{2}$ $>$ $M e C H_{2} C H = C H_{2}$ Because

$_{╱ C H_{3}}^{C H_{3} ╲} C = C_{╲ H}^{H ╱}$

6 $α - H y d r o g e n$

6 hyperconjugative structures

$_{╱ H}^{C H_{3} C H_{2} ╲} C = C_{╲ H}^{H ╱}$

$=> 2 α - H y d r o g e n$

2 Hyperconjugative structures

$∴ M e_{2} C = C H_{2} > M e C H_{2} C H = C H_{2}$ (stability)

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Similar questions

The stability of $M e_{2} C = C H_{2}$ is more than that of $M e C H_{2} C H = C H_{2}$ due to:

The stability of (CH₃)₂C=CH₂ is more than that of CH₃CH₂CH=CH₂ due to

C H_{3} O \oplus C H_{2}

C H_{3} \oplus C H_{2}

{M e}_{2} \oplus C H

C H_{3} C H_{2} \oplus C H_{2}

C H_{2} = C H - \oplus C H_{2}

C H_{3} C H_{2} \oplus C H_{2}

C H_{2} = \oplus C H

C H_{3} \oplus C H_{2}

+ C H_{2} - C H_{3}

+ C H_{2} - C H_{2} C l

+ C H_{2} - C H C l_{2}

+ C H_{2} - C C l_{3}

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