You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

SHE

The standard ...

Question

The standard cell potential for $Z n | Z n^{2 +} | | C u^{2 +} | C u i s 1.10 V .$ When the cell is completely discharged, $l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$ is closest to

37.3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.026

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.052

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
37.3

$Z n | Z n^{2 +} | | C u^{2 +} | C u; E_{C e l l}^{\circ} = 1.1 V 0 = E_{C e l l}^{\circ} - \frac{0.0591}{2} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}; - 1.1 = - \frac{0.0591}{2} l o g_{10} \frac{[Z n^{2 +}]}{[C u^{2 +}]} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]} = \frac{2.2}{0.0591} = 37.3$

Suggest Corrections

Similar questions

Q. The standard cell potential for

Z n | Z n^{2 +} | | C u^{2 +} | C u

is 1.10V. When the cell is completely discharged,

l o g [Z n^{2 +}] / [C u^{2 +}]

is closest to:

Q. The cell,

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u

, was allowed to be completely discharged at 298 K. The relative concentration of

Z n^{2 +}

C u^{2 +} (\frac{[Z n^{2 +}]}{[C u^{2 +}]})

is :

[E_{c e l l}^{0} = 1.10 V]

Q. The cell,

Z n (s) | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u (s) (E_{c e l l}^{\circ} = + 1.10 V)

was allowed to be completely discharged at

298 K

. The relative concentration of

Z n^{2 +}

C u^{2 +} (\frac{[Z n^{2 +}]}{[C u^{2 +}]})

is________.

Q. The cell,

Z n / {Z n}^{2} (1 M) / / {C u}^{2 +} (1 M) / C u

(

E_{c e l l}^{o} = 1.10 V

) was allowed to be completely discharged at

298 K

The relative concentration of

{Z n}^{2 +}

{C u}^{2 +}

is:

The cell, $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) |$ $C u (E_{c e l l}^{0} = 1.10 V)$ , was allowed to be completely discharged at 298 K. The relative concentration of $Z n^{2 +}$ to $C u^{2 +} (\frac{[Z n^{2 +}]}{[C u^{2 +}]})$ is :

Join BYJU'S Learning Program

The standard cell potential for Zn|Zn2+||Cu2+|Cu is 1.10V. When the cell is completely discharged, log[Zn2+][Cu2+] is closest to

The correct option is A 37.3 Zn|Zn2+||Cu2+|Cu; E∘Cell=1.1V0=E∘Cell−0.05912log[Zn2+][Cu2+]; −1.1=−0.05912log10[Zn2+][Cu2+]log[Zn2+][Cu2+]=2.20.0591=37.3

The standard cell potential for $Z n | Z n^{2 +} | | C u^{2 +} | C u i s 1.10 V .$ When the cell is completely discharged, $l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$ is closest to